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Kimyo "SVS"

kimyosvs
"SVS" ATM bilan, kimyo savollarini osonroq oʻrganing. "Siz ketdingiz biz qolarmidik yo Rasululloh" Kanal muallifi : Voxidov Sardor Sanjarovich Tel: +998 93 238 68 58 Murojat uchun: @Vokhidov_Sardor Manzil: Samarqand shahri , Rudakiy koʻchasi 237-uy.
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30 days
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Post views
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Posts (30d)
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Channel category
EDEducation Student Life
Audience gender
Female
Audience age
18-24
Audience financial status
Middle
Audience professions
Education
Summary
April 25, 16:27
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🔼
Tepadagi post aynan siz uchun
👆
Tezda qo'shiling Sertifikatchilar
👉
https://t.me/addlist/e0uDt8-Y7nMxZTRi
👉
https://t.me/addlist/e0uDt8-Y7nMxZTRi

April 25, 15:02
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⚡️
Milliy sertifikat natijalarini birinchi bo‘lib quyidagi kanallar orqali ko‘rishingiz mumkin
👇
tezda qo'shiling
❗️
👉
https://t.me/addlist/e0uDt8-Y7nMxZTRi

April 25, 09:21

Biologiya javobi xaliyam chiqmadimi???

April 24, 21:10
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9️⃣
Kechgacha ishlab chiqing , yechimlari kechga yuklanadi!
Manzil:
@kimyosvs

April 24, 21:10
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TEST - 9.pdf

April 24, 21:10
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1️⃣
0️⃣
Kechga yechimlari joylanadi , ishlab chiqing.
Manzil:
@kimyosvs

April 24, 21:10
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🔤
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8️⃣
yehimlari:
▶️
https://youtu.be/HihhimUaSws
Manzil:
@kimyosvs

April 24, 21:10
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☄️
⚡️
Tarjima testlarni savollari va yechimlarini ko'rib chiqayapmiz!
⚠️
Test - 1
💭
Savollar:
https://t.me/kimyosvs/7903
✔️
Yechim:
https://t.me/kimyosvs/7929
⚠️
Test - 2
💭
Savollar:
https://t.me/kimyosvs/7909
✔️
Yechim:
https://t.me/kimyosvs/7930
⚠️
Test - 3
💭
Savollar:
https://t.me/kimyosvs/7912
✔️
Yechim:
https://t.me/kimyosvs/7931
⚠️
Test - 4
💭
Savollar:
https://t.me/kimyosvs/7928
✔️
Yechim:
https://t.me/kimyosvs/7934
⚠️
Test - 5
💭
Savollar:
https://t.me/kimyosvs/7932
✔️
Yechim:
https://t.me/kimyosvs/7935
⚠️
Test - 6
💭
Savollar:
https://t.me/kimyosvs/7937
✔️
Yechim:
https://t.me/kimyosvs/7949
⚠️
Test - 7
💭
Savollar:
https://t.me/kimyosvs/7947
✔️
Yechim:
https://t.me/kimyosvs/7951
🚀
@kimyosvs
▶️
Kimyosvs

April 24, 19:19

Ertaga 4-va 6-guruhlardan qarzi borlar darsga qo’yilmaydi!

April 24, 10:30

𝑬𝑹𝑰𝑻𝑴𝑨 𝑲𝑶𝑵𝑺𝑬𝑵𝑻𝑹𝑨𝑻𝑺𝑰𝒀𝑨𝑺𝑰𝑵𝑰 𝑰𝑭𝑶𝑫𝑨𝑳𝑨𝑺𝑯 𝑼𝑺𝑼𝑳𝑳𝑨𝑹𝑰
1 - 𝑭𝑶𝑰𝒁 (%) bu 100 gr eritmani ichida erigan moddaning massasi.
Masalan - 30% li degani, 70 gr erituvchi 30 grammi erigan modda degani.
2 - 𝑴𝑶𝑳𝒀𝑨𝑹 (M yoki m/l) bilan ifodalanadi.
Ta'rifi: 1 l yani 1000 ml eritmani ichida erigan moddaning mollar sonini ko'rsatuvchi kattalik.
Masalan - 2 M li degani 1000 ml eritmani ichida erigam moddaning mol miqdori 2 mol ekan degani.
3 - 𝑵𝑶𝑹𝑴𝑨𝑳 (N yoki ekv/l) bilan ifodalanadi.
Ta'rifi: 1 l yani 1000 ml eritmani ichida erigan moddaning ekv (ekvivalent) miqdorini ko'rsatuvchi kattalik.
Masalan. 3 N li degani 1 l yani 1000 ml eritmani ichida erigan moddaning ekv miqdori 3 ekv ekan degani.
Yodga olamiz: Har qanday moddaning ekvivalent massasi uning 1 ekv ga teng. H2SO4 ning 1 ekvivalenti 49 gr.
4 - 𝑻𝑰𝑻𝑹 (T) bilan belgilanadi.
Tarifi: 1 ml eritmani ichida erigan moddani massasini ko'rsatuvchi kattalik.
Masalan. Titri 0,4 bo'lgan eritma degani 1 ml eritmani ichida erigan moddaning massasi 0,4 gr ekan degani.
𝑫𝑰𝑸𝑸𝑨𝑻 qilgan bo'lsangiz yuqoridagi
👆
👆
to'rtala konsentratsiya Eritmaning ichida erigan moddaning miqdorini ko'rsatuvchi konsentratsiyalar ekan.
Navbatdagi
👇
👇
👇
molyal konsentratsiya esa erituvchida erigan moddaning miqdorini ko'rsatuvchi kattalikdir.
5 - 𝑴𝑶𝑳𝒀𝑨𝑳 𝑲𝑶𝑵𝑺𝑬𝑵𝑻𝑹𝑨𝑻𝑺𝑰𝒀𝑨
(m/kg) bilan ifodalanadi.
Tarifi: 1 kg yani 1000 gr erituvchida erigan moddaning mol miqdorini ko'rsatuvchi kattalik.
𝒁𝑰𝑪𝑯𝑳𝑰𝑲 𝑽𝑨 𝑻𝑰𝑻𝑹𝑵𝑰 𝑭𝑨𝑹𝑸𝑰𝑵𝑰 𝑩𝑰𝑳𝑰𝑵𝑮
𝒁𝑰𝑪𝑯𝑳𝑰𝑲 - eritmaning 1 ml i necha necha gr kelishi. Yani p=1,25 g/ml degani eritmaning
1 ml i 1,25 gr degani.
𝑻𝑰𝑻𝑹 - eritmaning 1 ml ichida necha gr erigan modda borligi. Yani titri 0,35 degani 1 ml eritma ichida 0,35 gr erigan modda bor degani.
𝑴𝒂𝒔𝒂𝒍𝒂𝒏. Zichligi (p=1,25 gr/ml) bo'lgan eritmaning titri 0,35 ga teng bo'lsa, siz bilinki 1 ml eritma massasi 1,25 gr degani va uning ichida erigan modda massasi 0,35 gr ekan. Bundan malumki 1,25 gr eritma massasidan 0,35 gr erigan modda massasini ayirsak
(1,25 - 0,35 = 0,9) 0,9 gr erituvchi massasi kelib chiqarkan.
𝑶𝑫𝑫𝑰𝒀𝑹𝑶𝑸 𝑻𝑼𝑺𝑯𝑼𝑵𝑺𝑨𝑲
massada + massa = foiz
hajimda + mol = molyar
hajimda + ekv = normal
hajimda + massa = titr
massada + mol = molyal