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5 596October 14, 16:53
ln(y)=ln(1+1/n)ⁿ
Ln(y)=n•ln(1+1/n)
y'/y=ln(n+1)-1/(n+1)
y'=(1+1/n)ⁿ•(ln(n+1)-1/(n+1))
y'(1)=2(ln2-1/2)=2ln2-1
A kalit.
@mathematica0606
October 14, 16:49
Ikkala tomondan hosila olamiz va x=1 ni o'rniga qo'yamiz.
1+2x+3x²+4x³+...+50x⁴⁹=B(x)+B'(x)•(x-1)
1+2+3+4+....+50=B(1)+0
B(1)=(1+50)•25=51•25=1275
@mathematica0606
October 14, 16:43
Norjigitov
Olimpiada darslari uchun